3^x+3^x+1+(3^x)/8=11/8X=-1

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Solution for 3^x+3^x+1+(3^x)/8=11/8X=-1 equation: 



3^x+3^x+1+(3^x)/8=11/8x=-1

We move all terms to the left:

3^x+3^x+1+(3^x)/8-(11/8x)=0



Domain of the equation: 8x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3^x+3^x+3^x/8-(+11/8x)+1=0

We get rid of parentheses

3^x+3^x+3^x/8-11/8x+1=0

We calculate fractions


3^x+3^x+1=0

We move all terms containing x to the left, all other terms to the right

3^x+3^x=-1

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